JEE Main Physics Chapter-wise Quiz: 30 MCQs with Answers

This JEE Main physics chapter-wise quiz gives you 30 MCQs, five per chapter set, with a full answer key and worked solutions. Every chapter comes from the official JEE Main 2026 physics syllabus, which is still the base for 2027 preparation.

Use one set at the end of each chapter block in your 100-day JEE Main 2027 study plan, then come back to weak sets in the revision weeks. The same format is available for chemistry in our JEE Main chemistry chapter-wise quiz and for maths in the JEE Main maths chapter-wise quiz.

Notation: powers are written with ^, so v^2 means v squared and 10^-3 means 10 to the power minus 3. Use g = 10 m/s^2 unless a question says otherwise. μ0 = 4π × 10^-7 T m/A.

Which chapters does this JEE Main physics quiz cover?

The quiz covers six chapter sets that span 14 of the 20 physics units in the official NTA syllabus. Each set has five single-answer MCQs. Units and measurements, properties of solids and liquids, electromagnetic waves, atoms and nuclei, electronic devices and experimental skills are not tested here, so revise them separately.

For the full unit list and the topics removed in the 2024 revision, such as communication systems, see our JEE Main 2027 syllabus guide. NTA has not released a separate 2027 syllabus yet, so recheck when the 2027 bulletin comes out.

Set A: Can you solve these kinematics and laws of motion MCQs?

This set tests equations of motion, projectile range, static friction and a pulley system. Draw a free-body diagram for questions 4 and 5.

1. A ball is thrown vertically upward with a speed of 20 m/s. The maximum height it reaches is: (a) 10 m (b) 40 m (c) 20 m (d) 80 m
2. A projectile is fired at 20 m/s at an angle of 45° to the horizontal from level ground. Its horizontal range is: (a) 40 m (b) 20 m (c) 20√2 m (d) 80 m
3. A car starts from rest with a uniform acceleration of 2 m/s^2. The distance it covers in the 5th second alone is: (a) 25 m (b) 10 m (c) 16 m (d) 9 m
4. A 5 kg block rests on a horizontal floor. The coefficient of static friction is 0.3 and of kinetic friction is 0.2. A horizontal force of 10 N is applied to it. The friction force on the block is: (a) 15 N (b) 10 N (c) 20 N (d) zero
5. Masses of 3 kg and 2 kg hang from the two ends of a light string over a light, frictionless pulley. The tension in the string is: (a) 20 N (b) 30 N (c) 24 N (d) 12 N

Also readJEE Main Chemistry Chapter-wise Quiz: Physical and Organic

Set B: How well do you know work, energy, power and rotation?

Here you need spring energy, power, an inelastic collision, moment of inertia and rolling motion.

6. A spring of spring constant 200 N/m is compressed by 10 cm. The energy stored in it is: (a) 1 J (b) 2 J (c) 10 J (d) 20 J
7. A motor lifts a 50 kg load vertically through 10 m in 10 s at constant speed. The power delivered is: (a) 50 W (b) 5000 W (c) 250 W (d) 500 W
8. A 2 kg ball moving at 6 m/s hits a 1 kg ball at rest, and the two stick together. The loss in kinetic energy is: (a) 24 J (b) 12 J (c) 36 J (d) zero
9. The moment of inertia of a thin uniform rod of mass M and length L about an axis through one end, perpendicular to the rod, is: (a) ML^2/12 (b) ML^2/2 (c) ML^2/3 (d) ML^2
10. A solid sphere rolls without slipping on a level surface. The fraction of its total kinetic energy that is rotational is: (a) 2/5 (b) 2/7 (c) 5/7 (d) 1/2

Set C: Can you crack gravitation, SHM and waves MCQs?

This set checks escape velocity, g with height, the pendulum, energy in SHM and organ pipes. Write the proportionality first, numbers last.

11. The escape velocity from Earth is 11.2 km/s. For a planet with twice Earth's radius and the same mean density, the escape velocity is: (a) 11.2 km/s (b) 15.8 km/s (c) 5.6 km/s (d) 22.4 km/s
12. If g = 10 m/s^2 at Earth's surface, the value of g at a height equal to Earth's radius above the surface is: (a) 2.5 m/s^2 (b) 5 m/s^2 (c) 1.11 m/s^2 (d) 10 m/s^2
13. A simple pendulum has a time period of 2 s. If its length is made four times, the new time period is: (a) 8 s (b) 4 s (c) 2√2 s (d) 1 s
14. A particle performs SHM with amplitude A. Its kinetic energy equals its potential energy at a displacement of: (a) A/2 (b) √3A/2 (c) A/√2 (d) A/4
15. A pipe closed at one end is 85 cm long. If the speed of sound is 340 m/s, the fundamental frequency is: (a) 200 Hz (b) 50 Hz (c) 300 Hz (d) 100 Hz

Set D: How strong are you in thermodynamics and kinetic theory?

This set covers the first law, Carnot efficiency, RMS speed, γ and adiabatic compression. Always work in kelvin.

16. An ideal gas expands isothermally and does 500 J of work. The heat absorbed by the gas is: (a) zero (b) 500 J (c) −500 J (d) 1000 J
17. A Carnot engine works between 500 K and 300 K. Its efficiency is: (a) 40% (b) 60% (c) 66.7% (d) 25%
18. If the absolute temperature of an ideal gas is made four times, its RMS speed: (a) quadruples (b) halves (c) doubles (d) stays the same
19. For a diatomic ideal gas with no vibrational modes, the ratio γ = Cp/Cv is: (a) 1.67 (b) 1.33 (c) 1.29 (d) 1.4
20. A monatomic ideal gas at 300 K is compressed adiabatically to one-eighth of its volume. Its final temperature is: (a) 600 K (b) 1200 K (c) 2400 K (d) 4800 K

Also readJEE Mains 2027 Registration & Notification: Status on 11 Oct 2026

Set E: Can you answer these electrostatics and current electricity MCQs?

These questions test Coulomb's law, capacitors, stored energy, a stretched wire and terminal voltage. Convert microfarads carefully in question 23.

21. Two point charges repel each other with force F. If each charge is doubled and the distance between them is halved, the new force is: (a) 4F (b) 8F (c) F (d) 16F
22. A parallel plate capacitor has capacitance C in air. The plate separation is doubled and the gap is completely filled with a dielectric of constant K = 4. The new capacitance is: (a) 2C (b) C (c) 4C (d) 8C
23. The energy stored in a 10 μF capacitor charged to 100 V is: (a) 0.5 J (b) 0.05 J (c) 0.1 J (d) 5 × 10^-3 J
24. A wire of resistance 10 Ω is stretched uniformly to twice its length. Its new resistance is: (a) 20 Ω (b) 5 Ω (c) 40 Ω (d) 2.5 Ω
25. A cell of emf 12 V and internal resistance 1 Ω is connected to an external resistor of 5 Ω. The terminal voltage of the cell is: (a) 12 V (b) 2 V (c) 11 V (d) 10 V

Set F: How well do you know magnetism, EMI, modern physics and optics?

The last set mixes a current loop, a charge in a magnetic field, Faraday's law, the photoelectric effect and the lens formula. Use the sign convention in question 30.

26. A circular loop of radius 10 cm carries a current of 5 A. The magnetic field at its centre is: (a) 3.14 × 10^-5 T (b) 6.28 × 10^-5 T (c) 1.57 × 10^-5 T (d) 3.14 × 10^-7 T
27. A charged particle moves in a circle in a uniform magnetic field perpendicular to its velocity. If its speed is doubled, its time period of revolution: (a) doubles (b) halves (c) stays the same (d) quadruples
28. The magnetic flux through each turn of a 100-turn coil falls uniformly from 0.05 Wb to 0.01 Wb in 0.2 s. The average induced emf is: (a) 2 V (b) 20 V (c) 0.2 V (d) 200 V
29. Photons of energy 6 eV fall on a metal surface with work function 4 eV. The stopping potential is: (a) 4 V (b) 6 V (c) 10 V (d) 2 V
30. An object is placed 30 cm in front of a thin convex lens of focal length 20 cm. The image is: (a) 12 cm from the lens, magnification −0.4 (b) 60 cm on the other side, real, magnification −2 (c) 60 cm on the same side, virtual, magnification +2 (d) 15 cm on the other side, real, magnification −0.5

Answer key with explanations

Every calculation is shown, so you can see which step went wrong. Count a guessed answer as wrong even if it matched.

Set A answers

1. (c) 20 m. At the top, v = 0. Using v^2 = u^2 − 2gh: 0 = 400 − 2 × 10 × h, so h = 400/20 = 20 m.
2. (a) 40 m. R = u^2 sin 2θ / g = (400 × sin 90°)/10 = 400/10 = 40 m. 45° gives the maximum range for a given speed on level ground.
3. (d) 9 m. Distance in the nth second: s_n = u + a(2n − 1)/2 = 0 + 2 × 9/2 = 9 m. Check: distance in 5 s = 1/2 × 2 × 25 = 25 m; in 4 s = 16 m; difference = 9 m.
4. (b) 10 N. Limiting static friction = μs × mg = 0.3 × 5 × 10 = 15 N. The applied 10 N is less than 15 N, so the block stays at rest and static friction only balances the applied force: 10 N. Kinetic friction (0.2 × 50 = 10 N) applies only once the block slides.
5. (c) 24 N. a = (m1 − m2)g/(m1 + m2) = (3 − 2) × 10/5 = 2 m/s^2. For the 2 kg mass moving up: T − 20 = 2 × 2, so T = 24 N. Formula check: T = 2m1m2g/(m1 + m2) = 2 × 3 × 2 × 10/5 = 24 N.

Set B answers

6. (a) 1 J. U = 1/2 kx^2 = 1/2 × 200 × (0.1)^2 = 100 × 0.01 = 1 J. Convert 10 cm to 0.1 m first.
7. (d) 500 W. At constant speed, work = mgh = 50 × 10 × 10 = 5000 J. Power = 5000/10 = 500 W.
8. (b) 12 J. Momentum is conserved: 2 × 6 = 3 × v, so v = 4 m/s. Initial KE = 1/2 × 2 × 36 = 36 J. Final KE = 1/2 × 3 × 16 = 24 J. Loss = 36 − 24 = 12 J.
9. (c) ML^2/3. About the centre, I = ML^2/12. By the parallel axis theorem, I(end) = ML^2/12 + M(L/2)^2 = ML^2/12 + 3ML^2/12 = ML^2/3.
10. (b) 2/7. For a solid sphere, I = 2/5 mR^2 and ω = v/R, so KE(rot) = 1/2 × 2/5 mR^2 × v^2/R^2 = 1/5 mv^2. KE(trans) = 1/2 mv^2. Total = 7/10 mv^2. Fraction = (1/5)/(7/10) = 2/7.

Set C answers

11. (d) 22.4 km/s. v_e = √(2GM/R). With M = (4/3)πR^3ρ, v_e = R√(8πGρ/3), so v_e is proportional to R at fixed density. Doubling R doubles v_e: 2 × 11.2 = 22.4 km/s.
12. (a) 2.5 m/s^2. g(h) = g × R^2/(R + h)^2. With h = R, g(h) = g/4 = 10/4 = 2.5 m/s^2.
13. (b) 4 s. T = 2π√(L/g), so T is proportional to √L. Four times the length gives √4 = 2 times the period: 2 × 2 = 4 s.
14. (c) A/√2. PE = 1/2 kx^2 and KE = 1/2 k(A^2 − x^2). Setting them equal: x^2 = A^2 − x^2, so x^2 = A^2/2 and x = A/√2.
15. (d) 100 Hz. For a pipe closed at one end, the fundamental has L = λ/4, so f = v/(4L) = 340/(4 × 0.85) = 340/3.4 = 100 Hz.

Set D answers

16. (b) 500 J. In an isothermal process for an ideal gas, ΔU = 0. By the first law, Q = ΔU + W = 0 + 500 = 500 J absorbed.
17. (a) 40%. η = 1 − T(cold)/T(hot) = 1 − 300/500 = 1 − 0.6 = 0.4, or 40%.
18. (c) doubles. v(rms) = √(3RT/M), so v(rms) is proportional to √T. Four times T gives √4 = 2 times the RMS speed.
19. (d) 1.4. A rigid diatomic molecule has 5 degrees of freedom, so Cv = 5R/2 and Cp = Cv + R = 7R/2. γ = (7/2)/(5/2) = 7/5 = 1.4.
20. (b) 1200 K. For an adiabatic process, TV^(γ − 1) is constant. For a monatomic gas, γ = 5/3, so γ − 1 = 2/3. T2 = T1 × (V1/V2)^(2/3) = 300 × 8^(2/3) = 300 × 4 = 1200 K.

Set E answers

21. (d) 16F. F = kq1q2/r^2. New force = k(2q1)(2q2)/(r/2)^2 = 4kq1q2/(r^2/4) = 16 kq1q2/r^2 = 16F.
22. (a) 2C. C = Kε0A/d. Multiplying by K = 4 and dividing by 2 for the doubled separation gives 4C/2 = 2C.
23. (b) 0.05 J. U = 1/2 CV^2 = 1/2 × 10 × 10^-6 × (100)^2 = 1/2 × 10^-5 × 10^4 = 0.05 J.
24. (c) 40 Ω. Volume stays constant, so doubling the length halves the area. R = ρL/A becomes ρ(2L)/(A/2) = 4R = 4 × 10 = 40 Ω.
25. (d) 10 V. I = E/(R + r) = 12/(5 + 1) = 2 A. Terminal voltage V = E − Ir = 12 − 2 × 1 = 10 V, which also equals IR = 2 × 5 = 10 V.

Set F answers

26. (a) 3.14 × 10^-5 T. B = μ0I/(2R) = (4π × 10^-7 × 5)/(2 × 0.1) = (20π × 10^-7)/0.2 = π × 10^-5 ≈ 3.14 × 10^-5 T.
27. (c) stays the same. r = mv/(qB), so the radius doubles with speed. But T = 2πr/v = 2πm/(qB), which does not depend on speed. This is why a cyclotron can use a fixed frequency.
28. (b) 20 V. e = N × Δφ/Δt = 100 × (0.05 − 0.01)/0.2 = 100 × 0.04/0.2 = 100 × 0.2 = 20 V.
29. (d) 2 V. K(max) = hν − φ = 6 − 4 = 2 eV. Stopping potential V0 = K(max)/e = 2 V.
30. (b) 60 cm on the other side, real, magnification −2. With u = −30 cm and f = +20 cm, 1/v − 1/u = 1/f gives 1/v = 1/20 − 1/30 = 1/60, so v = +60 cm (real, on the far side). m = v/u = 60/(−30) = −2, so the image is inverted and twice the size.

How should you score and use this physics quiz?

Give yourself one mark per correct answer and judge each set separately. A set score tells you which chapter to reopen before your next mock; a total out of 30 cannot.

Label each mistake as wrong formula, wrong concept (like using kinetic friction on a block at rest) or a units slip. Mostly units slips means slow down; mostly concept errors means go back to theory.

How does this quiz fit into the 100-day plan for JEE Main 2027?

Use one set at the end of each chapter block in the 100-day plan, retake low-scoring sets during the revision weeks, and switch to full-length timed papers in the final phase. Chapter-wise quizzes find weak topics; mock tests train speed and question selection across all three subjects.

When most of your sets score 4 or 5, start the official NTA mocks; our guide to JEE Main 2027 free mock tests explains where to find them and how to review them. JEE Main 2027 Session 1 dates have been announced in NTA's official calendar (tentative), and registration is not open yet.

Every extra mark in physics lifts your percentile, and percentile decides which colleges are realistic. Our pillar guide on colleges for low JEE Main rank shows how much the band you land in matters.

Final Word: make this JEE Main physics chapter-wise quiz a habit

This JEE Main physics chapter-wise quiz works best when you repeat it: take each set after its chapters and retake weak sets after a week.

• Attempt each set in about 7 minutes without notes or a calculator.
• Check the working in the answer key, not just the option letter.
• Label every mistake as formula, concept or units, and fix the pattern.
• Revise units not covered here: measurements, solids and liquids, EM waves, atoms and nuclei, electronic devices and experiments.
• Move to NTA mock tests once most sets score 4 or 5.